Seward Township, Winnebago County, Illinois

Seward Township
Township
Combined township building and fire station

Location in Winnebago County
Coordinates: 42°14′45″N 89°20′19″W / 42.24583°N 89.33861°W / 42.24583; -89.33861Coordinates: 42°14′45″N 89°20′19″W / 42.24583°N 89.33861°W / 42.24583; -89.33861
Country United States
State Illinois
County Winnebago
Established November 6, 1849 (1849-11-06)
Government
 • Supervisor Garelt S. Stahl
Area
 • Total 35.82 sq mi (92.8 km2)
 • Land 35.81 sq mi (92.7 km2)
 • Water 0 sq mi (0 km2)  0%
Elevation 853 ft (260 m)
Population (2010)
 • Estimate (2016)[1] 889
 • Density 25.6/sq mi (9.9/km2)
Time zone UTC-6 (CST)
 • Summer (DST) UTC-5 (CDT)
FIPS code 17-201-68783
[2][3]

Seward Township is located in Winnebago County, Illinois. As of the 2010 census, its population was 917 and it contained 394 housing units.[4]

Geography

According to the 2010 census, the township has a total area of 35.82 square miles (92.8 km2), all land.[4]

Demographics

Historical population
CensusPop.%±
Est. 2016889[1]
U.S. Decennial Census[5]

References

  1. 1 2 "Population and Housing Unit Estimates". Retrieved June 9, 2017.
  2. ↑ U.S. Geological Survey Geographic Names Information System: Township of Seward
  3. ↑ Illinois Regional Archives Depository System. "Name Index to Illinois Local Governments". Illinois State Archives. Illinois Secretary of State. Retrieved 19 September 2014.
  4. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-28.
  5. ↑ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.


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