Pickaway Township, Shelby County, Illinois

Pickaway Township
Township

Location of Illinois in the United States
Coordinates: 39°33′47″N 88°52′09″W / 39.56306°N 88.86917°W / 39.56306; -88.86917Coordinates: 39°33′47″N 88°52′09″W / 39.56306°N 88.86917°W / 39.56306; -88.86917
Country United States
State Illinois
County Shelby
Organized November 8, 1859
Area
 • Total 29.7 sq mi (77 km2)
 • Land 29.7 sq mi (77 km2)
 • Water 0 sq mi (0 km2)
Elevation 718 ft (219 m)
Population (2010)
 • Estimate (2016)[1] 172
 • Density 6/sq mi (2/km2)
Time zone UTC-6 (CST)
 • Summer (DST) UTC-5 (CDT)
ZIP code XXXXX
Area code(s) 217
FIPS code 17-173-59663

Pickaway Township is located in Shelby County, Illinois. As of the 2010 census, its population was 179 and it contained 74 housing units.[2]

Geography

According to the 2010 census, the township has a total area of 29.7 square miles (77 km2), all land.[2]

Demographics

Historical population
CensusPop.%±
Est. 2016172[1]
U.S. Decennial Census[3]

References

  1. 1 2 "Population and Housing Unit Estimates". Retrieved June 9, 2017.
  2. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-28.
  3. ↑ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.


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