United States presidential election in Michigan, 1896

United States presidential election in Michigan, 1896
November 3, 1896

 
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 14 0
Popular vote 293,336 237,166
Percentage 53.77% 43.47%
President before election

Grover Cleveland
Democratic

 Elected President

William McKinley
Republican

The 1896 United States presidential election in Michigan took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Michigan voters chose fourteen electors to the Electoral College, which selected the president and vice president.

Michigan was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey.

Results

United States presidential election in Michigan, 1896[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 293,336 53.77% 14
Democratic William Jennings Bryan 237,166 43.47% 0
National Democratic John M. Palmer 6,923 1.27% 0
Prohibition Joshua Levering 4,978 0.91% 0
National Prohibition Charles Bentley 1,816 0.33% 0
Write-ins Scattered 1,073 0.20% 0
Socialist Labor Charles Matchett 293 0.05% 0
Totals 545,585 100.00% 14
Voter turnout —

References

  1. ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Michigan

Notes

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