United States presidential election in Wisconsin, 1896

United States presidential election, 1896

November 3, 1896

 
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 12 0
Popular vote 268,135 165,523
Percentage 59.93% 37.0%

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Wisconsin was held on November 3, 1896. Wisconsin voters chose twelve electors to the Electoral College, who voted for president and vice president.

Republican Party candidate William McKinley won the state with 60% of the popular vote, winning Wisconsin's twelve electoral votes.[1]

Results

United States presidential election in Wisconsin, 1896
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 268,135 59.93% 12
Democratic William Jennings Bryan 165,523 37.0% 0
Prohibition Joshua Levering 7,507 1.68% 0
National Democratic John M. Palmer 4,584 1.02% 0
Socialist Labor Charles H. Matchett 1,314 0.29% 0
National Prohibition Charles E. Bentley 346 0.08% 0
Totals 447,409 100.0% 12

References

  1. "1896 Presidential General Election Results - Wisconsin". Retrieved August 18, 2016.
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