United States presidential election in Delaware, 1896

United States presidential election in Delaware, 1896
November 3, 1896

 
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 3 0
Popular vote 20,450 16,574
Percentage 53.18% 43.10%
President before election

Grover Cleveland
Democratic

 Elected President

William McKinley
Republican

The 1896 United States presidential election in Delaware took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Delaware voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey.

Results

United States presidential election in Delaware, 1896[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 20,450 53.18% 3
Democratic William Jennings Bryan 16,574 43.10% 0
National Democratic John M. Palmer 966 2.51% 0
Prohibition Joshua Levering 466 1.21% 0
Totals 38,456 100.00% 3
Voter turnout —

References

  1. ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Delaware

Notes

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