United States presidential election in Connecticut, 1896

United States presidential election in Connecticut, 1896
November 3, 1896

 
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 6 0
Popular vote 110,285 56,740
Percentage 63.24% 32.54%
President before election

Grover Cleveland
Democratic

 Elected President

William McKinley
Republican

The 1896 United States presidential election in Connecticut took place on November 3, 1896. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Connecticut voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won the state by a margin of 30.7%. This was the first time a Republican carried Connecticut in a presidential election since James A. Garfield did so 16 years earlier.

Results

United States presidential election in Connecticut, 1896[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William McKinley of Ohio Garret Hobart of New Jersey 110,285 63.24% 6 100.00%
Democratic William Jennings Bryan of Nebraska Arthur Sewall of Maine 56,740 32.54% 0 0.00%
National Democratic John McAuley Palmer of Illinois Simon Bolivar Buckner of Kentucky 4,336 2.49% 0 0.00%
Prohibition Joshua Levering of Maryland Hale Johnson of Illinois 1,806 1.04% 0 0.00%
Socialist Labor Charles Horatio Matchett of New York Matthew Maguire of New Jersey 1,223 0.70% 0 0.00%
Total 174,390 100.00% 6 100.00%

References

  1. ↑ "1896 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 23 December 2013.
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