United States presidential election in Michigan, 1928
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All 15 Michigan votes to the Electoral College | ||||||||||||||||||||||||||
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Elections in Michigan | ||||||||||
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The 1928 United States presidential election in Michigan took place on November 6, 1928, as part of the 1928 United States presidential election. Michigan voters chose fifteen[1] representatives, or electors, to the Electoral College, who voted for president and vice president.
Michigan voted for Republican nominees Herbert Hoover of California and his running mate Charles Curtis in a landslide. The ticket received slightly over 70% of the popular vote compared to the Democrat's Al Smith of New York and Joseph T. Robinson's 28.92%.[2][3]
With 70.36% of the popular vote, Michigan would prove to be Hoover's second strongest victory in the nation after Kansas[4].
As of 2018, this remains the last time the Republican candidate carried Wayne County, home of Michigan's most populated city, Detroit.
Results
Party | Candidate | Votes | % | |
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Republican | Herbert Hoover | 965,396 | 70.36% | |
Democratic | Al Smith | 396,762 | 28.92% | |
Socialist | Norman Thomas | 3,516 | 0.26% | |
Workers Party | William Z. Foster | 2,881 | 0.21% | |
Prohibition | William F. Varney | 2,728 | 0.20% | |
Socialist Labor | Verne L. Reynolds | 799 | 0.06% | |
Total votes | 1,372,082 | 100% |
References
- ↑ "1928 Election for the Thirty-Sixth Term (1929-1933)". Retrieved 2018-04-03.
- ↑ "1928 Presidential General Election Results - Michigan". Retrieved 2018-04-03.
- ↑ "The American Presidency Project - Election of 1928". Retrieved 2018-04-03.
- ↑ "1928 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.