United States presidential election in Michigan, 1928

United States presidential election in Michigan, 1928

November 6, 1928

All 15 Michigan votes to the Electoral College

 
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 15 0
Popular vote 965,396 396,762
Percentage 70.36% 28.92%

President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

The 1928 United States presidential election in Michigan took place on November 6, 1928, as part of the 1928 United States presidential election. Michigan voters chose fifteen[1] representatives, or electors, to the Electoral College, who voted for president and vice president.

Michigan voted for Republican nominees Herbert Hoover of California and his running mate Charles Curtis in a landslide. The ticket received slightly over 70% of the popular vote compared to the Democrat's Al Smith of New York and Joseph T. Robinson's 28.92%.[2][3]

With 70.36% of the popular vote, Michigan would prove to be Hoover's second strongest victory in the nation after Kansas[4].

As of 2018, this remains the last time the Republican candidate carried Wayne County, home of Michigan's most populated city, Detroit.

Results

United States presidential election in Michigan, 1928
Party Candidate Votes %
Republican Herbert Hoover 965,396 70.36%
Democratic Al Smith 396,762 28.92%
Socialist Norman Thomas 3,516 0.26%
Workers Party William Z. Foster 2,881 0.21%
Prohibition William F. Varney 2,728 0.20%
Socialist Labor Verne L. Reynolds 799 0.06%
Total votes 1,372,082 100%

References

  1. "1928 Election for the Thirty-Sixth Term (1929-1933)". Retrieved 2018-04-03.
  2. "1928 Presidential General Election Results - Michigan". Retrieved 2018-04-03.
  3. "The American Presidency Project - Election of 1928". Retrieved 2018-04-03.
  4. "1928 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
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