United States presidential election in Michigan, 1904
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All 14 Michigan votes to the Electoral College | ||||||||||||||||||||||||||
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Elections in Michigan | ||||||||||
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The 1904 United States presidential election in Michigan took place on November 8, 1904, as part of the 1904 United States presidential election. Michigan voters chose fourteen[1] representatives, or electors, to the Electoral College, who voted for president and vice president.
Republican Party candidate and incumbent Theodore Roosevelt won Michigan in a landslide, garnering nearly 70% of the popular vote. Democratic challenger Alton B. Parker received 25.79% of ballots cast.[2]
Results
Party | Candidate | Votes | % | |
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Republican | Theodore Roosevelt (inc.) | 364,957 | 69.51% | |
Democratic | Alton B. Parker | 135,392 | 25.79% | |
Prohibition | Silas C. Swallow | 13,441 | 2.56% | |
Socialist | Eugene V. Debs | 9,042 | 1.72% | |
People's | Thomas E. Watson | 1,159 | 0.22% | |
Socialist Labor | Charles Corregan | 1,036 | 0.20% | |
Total votes | 525,027 | 100% |
References
- ↑ "1904 Election for the Thirtieth Term (1905-1909)". Retrieved 2018-04-03.
- ↑ "1904 Presidential General Election Results - Michigan". Retrieved 2018-04-03.
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