United States presidential election in Missouri, 1896
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Elections in Missouri | ||||||||||||||||
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The 1896 United States presidential election in Missouri took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Missouri voters chose seventeen electors to the Electoral College, which selected the president and vice president.
Missouri was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Arthur Sewall of Maine. Four electors cast their Vice Presidential ballots for Thomas E. Watson. This is the only election since the Civil War where Douglas County voted for a Democratic presidential candidate.[1]
Results
United States presidential election in Missouri, 1896[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | William Jennings Bryan | 363,667 | 53.96% | 17 | |
Republican | William McKinley | 304,940 | 45.25% | 0 | |
National Democratic | John M. Palmer | 2,365 | 0.35% | 0 | |
Prohibition | Joshua Levering | 2,043 | 0.30% | 0 | |
Socialist Labor | Charles Matchett | 599 | 0.09% | 0 | |
National Prohibition | Charles Bentley | 292 | 0.04% | 0 | |
Totals | 673,906 | 100.00% | 17 | ||
Voter turnout | — |
Notes
References
- ↑ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 31, 239-246 ISBN 0786422173
- ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Missouri
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