United States presidential election in Delaware, 1940

United States presidential election in Delaware, 1940
November 5, 1940[1]
All 3 Delaware votes to the Electoral College

 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York Indiana
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 3 0
Popular vote 74,599 61,440
Percentage 54.7% 45.1%
President before election

Franklin D. Roosevelt
Democratic

 Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Delaware took place on November 5, 1940, as part of the 1940 United States presidential election. Delaware voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Delaware was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 54.70% of the popular vote, against Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 45.05% of the popular vote.[3][4]

Results

United States presidential election in Delaware, 1940
Party Candidate Votes %
Democratic Franklin D. Roosevelt (inc.) 74,599 54.70%
Republican Wendell Willkie 61,440 45.05%
Write-in 335 0.25%
Total votes 136,334 100%

References

  1. ↑ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved August 20, 2018.
  2. ↑ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 20, 2018.
  3. ↑ "1940 Presidential General Election Results - Delaware". Retrieved August 20, 2018.
  4. ↑ "The American Presidency Project - Election of 1940". Retrieved August 20, 2018.
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