United States presidential election in Delaware, 1892
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Elections in Delaware | ||||||||||
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The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Delaware voters chose three electors to the Electoral College, which selected the president and vice president.
Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.
Results
United States presidential election in Delaware, 1892[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Grover Cleveland | 18,581 | 49.90% | 3 | |
Republican | Benjamin Harrison (incumbent) | 18,077 | 48.55% | 0 | |
Prohibition | John Bidwell | 564 | 1.51% | 0 | |
Write-ins | Scattered | 13 | 0.03% | 0 | |
Totals | 37,235 | 100.00% | 3 | ||
Voter turnout | — |
References
- ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Delaware
Notes
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Wikipedia.
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