United States presidential election in Delaware, 1900

United States presidential election in Delaware, 1900
November 6, 1900

 
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 3 0
Popular vote 22,535 18,852
Percentage 53.67% 44.90%
President before election

William McKinley
Republican

 Elected President

William McKinley
Republican

The 1900 United States presidential election in Delaware took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Delaware voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.

Results

United States presidential election in Delaware, 1900[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 22,535 53.67% 3
Democratic William Jennings Bryan 18,852 44.90% 0
Prohibition John Woolley 546 1.30% 0
Social Democratic Eugene Debs 56 0.13% 0
Totals 41,989 100.00% 3
Voter turnout —

References

  1. ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Delaware

Notes

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