United States presidential election in Indiana, 1940

United States presidential election in Indiana, 1940
November 5, 1940[1]
All 14 Indiana votes to the Electoral College

 
Nominee Wendell Willkie Franklin D. Roosevelt
Party Republican Democratic
Home state Indiana New York
Running mate Charles L. McNary Henry A. Wallace
Electoral vote 14 0
Popular vote 899,466 874,063
Percentage 50.5% 49.0%
President before election

Franklin D. Roosevelt
Democratic

 Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Indiana took place on November 5, 1940, as part of the 1940 United States presidential election. Indiana voters chose fourteen[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Indiana was won by Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 50.45% of the popular vote, against incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 49.03% of the popular vote.[3][4]

Results

United States presidential election in Indiana, 1940
Party Candidate Votes %
Republican Wendell Willkie 899,466 50.45%
Democratic Franklin D. Roosevelt (inc.) 874,063 49.03%
Prohibition Roger Babson 6,437 0.36%
Write-in 2,781 0.16%
Total votes 1,782,747 100%

References

  1. ↑ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved August 18, 2018.
  2. ↑ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 18, 2018.
  3. ↑ "1940 Presidential General Election Results - Indiana". Retrieved August 18, 2018.
  4. ↑ "The American Presidency Project - Election of 1940". Retrieved August 18, 2018.
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