United States presidential election in Delaware, 1932

United States presidential election in Delaware, 1932

November 8, 1932

Nominee Herbert Hoover Franklin D. Roosevelt Party Republican Democratic Home state California New York Running mate Charles Curtis John Nance Garner Electoral vote 3 0 Popular vote 57,073 54,319 Percentage 50.55% 48.11%

President before election Herbert Hoover Republican Elected President Franklin D. Roosevelt Democratic

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The 1932 United States presidential election in Delaware took place on November 8, 1932, as part of the 1932 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Delaware voted for the Republican nominee, incumbent President Herbert Hoover of California, over the Democratic nominee, Governor Franklin D. Roosevelt of New York. Hoover's running mate was incumbent Vice President Charles Curtis of Kansas, while Roosevelt ran with incumbent Speaker of the House John Nance Garner of Texas.

Hoover won the state by a narrow margin of 2.44 percent, making Delaware one of the only six states which voted to re-elect the embattled Republican incumbent president, who was widely unpopular over his failure to adequately address the Great Depression.

With 50.55% of the popular vote. it was his fourth strongest state in the nation after Vermont, Maine and neighboring Pennsylvania^[1].

Results

References