United States presidential election in Delaware, 1828

United States presidential election in Delaware, 1828

October 31 – December 2, 1828

Nominee John Quincy Adams Party National Republican Home state Massachusetts Running mate Richard Rush Electoral vote 3

Elections in Delaware
Federal government Presidential elections 1788-89 1792 1796 1800 1804 1808 1812 1816 1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential primaries Democratic 2004 2008 2016 Republican 2008 2012 U.S. Senate elections 1790 1795 1797 1802 1972 1976 1978 1982 1984 1988 1990 1994 1996 2000 2002 2006 2008 2012 2014 2018 U.S. House elections 1789 1790 1792 1794 1796 1798 1800 1802 1804 2006 2008 2010 2012 2014 2016 2018 Special elections Senate, 2010
State government General elections 2010 2012 2014 2016 2018 Gubernatorial elections 1988 1992 1996 2000 2004 2008 2012 2016 2020 Lieutenant gubernatorial elections 2004 2008 2012 2016 House of Representatives elections 2008 2010 2012 2014 2016 Special elections 10th Senate district, 2017
Wilmington Mayoral elections 2012 2016

The 1828 United States presidential election in Delaware took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware cast three electoral votes for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote.^[1]

Results

References