United States presidential election in Delaware, 1864

United States presidential election in Delaware, 1864

November 8, 1864

 
Nominee George B. McClellan Abraham Lincoln
Party Democratic National Union
Home state Pennsylvania Illinois
Running mate George H. Pendleton Andrew Johnson
Electoral vote 3 0
Popular vote 8,767 8,155
Percentage 51.81% 48.19%

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
Republican

The 1864 United States presidential election in Delaware took place on November 8, 1864, as part of the 1864 United States presidential election. Delaware voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president[1].

Delaware was won by the 4th Commanding General of the United States Army George B. McClellan (DPennsylvania), running with Representative George H. Pendleton, with 51.81% of the popular vote against the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 48.19% of the popular vote[1].

Results

United States presidential election in Delaware, 1864[1]
Party Candidate Votes %
Democratic John C. Breckinridge 8,767 51.81%
National Union Abraham Lincoln 8,155 48.19%
Total votes 16,922 100.00%

References

  1. 1 2 3 "1864 Presidential Election Results Delaware".
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