United States presidential election in Idaho, 1940

United States presidential election in Idaho, 1940

November 5, 1940[1]
All 4 Idaho votes to the Electoral College
Nominee Franklin D. Roosevelt Wendell Willkie Party Democratic Republican Home state New York Indiana Running mate Henry A. Wallace Charles L. McNary Electoral vote 4 0 Popular vote 127,842 106,553 Percentage 54.4% 45.3%
President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

Elections in Idaho
Federal government Presidential elections 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential primaries Democratic Caucuses 2008 Republican Primaries 2008 2012 U.S. Senate elections 1980 1986 1990 1992 1996 1998 2002 2004 2008 2010 2014 2016 U.S. House elections 2006 2008 2010 2012 2014 2016 2018
State government General elections 2014 Gubernatorial elections 1982 1986 1990 1994 1998 2002 2006 2010 2014 2018 State legislature elections 2006
Ballot measures Gubernatorial elections Amendment 2 Proposition 2

The 1940 United States presidential election in Idaho took place on November 5, 1940, as part of the 1940 United States presidential election. Idaho voters chose four^[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Idaho was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 54.36% of the popular vote, against Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 45.31% of the popular vote.^[3][4]

Results

References