United States presidential election in Oklahoma, 1940
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All 11 Oklahoma votes to the Electoral College | ||||||||||||||||||||||||||
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Elections in Oklahoma |
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The 1940 United States presidential election in Oklahoma took place on November 5, 1940, as part of the 1940 United States presidential election. Oklahoma voters chose eleven[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Oklahoma was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 57.41% of the popular vote, against Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 42.23% of the popular vote.[3][4]
Results
Party | Candidate | Votes | % | |
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Democratic | Franklin D. Roosevelt (inc.) | 474,313 | 57.41% | |
Republican | Wendell Willkie | 348,872 | 42.23% | |
Prohibition | Roger Babson | 3,027 | 0.37% | |
Total votes | 826,212 | 100% |
References
- ↑ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved September 11, 2018.
- ↑ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved September 11, 2018.
- ↑ "1940 Presidential General Election Results - Oklahoma". Retrieved September 11, 2018.
- ↑ "The American Presidency Project - Election of 1940". Retrieved September 11, 2018.
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