United States presidential election in Indiana, 1864

United States presidential election in Indiana, 1864

November 8, 1864

Nominee Abraham Lincoln George B. McClellan Party National Union Democratic Home state Illinois Pennsylvania Running mate Andrew Johnson George H. Pendleton Electoral vote 13 0 Popular vote 150,422 130,233 Percentage 53.60% 46.40%

President before election Abraham Lincoln Republican Elected President Abraham Lincoln Republican

Elections in Indiana
Federal government Presidential Elections 1816 1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential Primaries Democratic 2008 2016 Republican 2008 2012 2016 U.S. Senate Elections 1914–1974 1976 1980 1982 1986 1988 1992 1994 1998 2000 2004 2006 2010 2012 2016 2018 U.S. House Elections 1996 1998 2000 2002 2004 2006 (7th) 2008 2010 2012 2014 2016 2018 Special elections Senate, 1990 7th district, 2008 3rd district, 2010
State government State elections 2010 2012 2014 2016 Gubernatorial elections 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 2020
Indianapolis Mayoral Elections 2007 2011 2015 City-County Council Elections 2007 2011 2015

The 1864 United States presidential election in Indiana took place on November 8, 1864, as part of the 1864 United States presidential election. Indiana voters chose thirteen representatives, or electors, to the Electoral College, who voted for president and vice president^[1].

Indiana was won by the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 53.60% of the popular vote, against the 4th Commanding General of the United States Army George B. McClellan (D–Pennsylvania), running with Representative George H. Pendleton, with 46.40% of the vote.^[1]

Results

References