United States presidential election in Indiana, 1856

United States presidential election in Indiana, 1856
November 4, 1856

 
Nominee James Buchanan John C. Frémont Millard Fillmore
Party Democratic Republican American
Home state Pennsylvania California New York
Running mate John C. Breckinridge William L. Dayton Andrew Jackson Donelson
Electoral vote 13 0 0
Popular vote 118,670 94,375 22,386
Percentage 50.41% 40.09% 9.51%
President before election

Franklin Pierce
Democratic

 Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Indiana took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose thirteen representatives, or electors to the Electoral College, who voted for president and vice president.

Indiana voted for the Democratic candidate, James Buchanan, over Republican candidate John C. Frémont and American Party candidate Millard Fillmore. Buchanan won Indiana by a margin of 10.32%.

Results

United States presidential election in Indiana, 1856[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 118,670 50.41% 13 100.00%
Republican John C. Frémont of California William L. Dayton of New Jersey 94,375 40.09% 0 0.00%
American Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 22,386 9.51% 0 0.00%
Total 235,431 100.00% 13 100.00%

References

  1. ↑ "1856 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 3 December 2017.
  2. ↑ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.
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