United States presidential election in Indiana, 1844
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Elections in Indiana | ||||||||||
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The 1844 United States presidential election in Indiana took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.
Indiana voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Indiana by a margin of 1.65%.
Results
United States presidential election in Indiana, 1844[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 70,181 | 50.07% | 12 | 100.00% | ||
Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 67,867 | 48.42% | 0 | 0.00% | ||
Liberty | James G. Birney of Michigan | Thomas Morris of Ohio | 2,106 | 1.50% | 0 | 0.00% | ||
Total | 140,154 | 100.00% | 12 | 100.00% |
References
- ↑ "1844 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 23 December 2013.
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