United States presidential election in Iowa, 1892
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Elections in Iowa |
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The 1892 United States presidential election in Iowa took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Iowa voters chose thirteen electors to the Electoral College, which selected the president and vice president.
Iowa was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York.
Results
United States presidential election in Iowa, 1892[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | Benjamin Harrison (incumbent) | 219,795 | 49.60% | 13 | |
Democratic | Grover Cleveland | 196,367 | 44.31% | 0 | |
People's | James Weaver | 20,595 | 4.65% | 0 | |
Prohibition | John Bidwell | 6,402 | 1.44% | 0 | |
Totals | 443,159 | 100.00% | 13 | ||
Voter turnout | — |
References
- ↑ Dave Leip’s U.S. Election Atlas; https://uselectionatlas.org/RESULTS/state.php?fips=19&year=1892&f=0&off=0&elect=0 Presidential General Election Results – Iowa]
Notes
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