United States presidential election in Minnesota, 1892
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The 1892 United States presidential election in Minnesota took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.
Minnesota was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York. Minnesota was the state where Bidwell performed the best and the only one where he broke 5%.
Results
United States presidential election in Minnesota, 1892[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | Benjamin Harrison (incumbent) | 122,823 | 45.96% | 9 | |
Democratic | Grover Cleveland | 100,920 | 37.76% | 0 | |
People's | James Weaver | 29,313 | 10.97% | 0 | |
Prohibition | John Bidwell | 14,182 | 5.31% | 0 | |
Totals | 267,238 | 100.00% | 9 | ||
Voter turnout | — |
References
- ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Minnesota
Notes
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