United States presidential election in Wisconsin, 1892
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Elections in Wisconsin | ||||||
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The 1892 United States presidential election in Wisconsin was held on November 8, 1892. Wisconsin voters chose twelve electors to the Electoral College, who voted for president and vice president.
Democratic Party candidate Grover Cleveland won the state with 48% of the popular vote, winning Wisconsin's twelve electoral votes.[1] This marked the first time since 1852 where the Democratic candidate carried Wisconsin.
Results
United States presidential election in Wisconsin, 1892 | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Grover Cleveland | 177,325 | 47.72% | 12 | |
Republican | Benjamin Harrison (incumbent) | 171,101 | 46.05% | 0 | |
Prohibition | John Bidwell | 13,136 | 3.54% | 0 | |
People's | James Weaver | 10,019 | 2.7% | 0 | |
Totals | 371,581 | 100.0% | 12 | ||
References
- ↑ "1892 Presidential General Election Results - Wisconsin". Retrieved August 18, 2016.
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