United States presidential election in North Dakota, 1892
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Elections in North Dakota |
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The 1892 United States presidential election in North Dakota took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. North Dakota voters chose three electors to the Electoral College, which selected the president and vice president.
North Dakota was won by the Populist nominees, James B. Weaver of Iowa and his running mate James G. Field of Virginia. Weaver and Field defeated the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York. Two electors from the Democratic-Populist Fusion ticket won and one Republican Elector won. This created a split delegation of electors: one for Weaver, one for Harrison, and one for Cleveland. This is the only time in a US presidential election that a state has equally distributed its electoral votes between three candidates.
Results
United States presidential election in North Dakota, 1892[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
People's | James Weaver | 17,700 | 49.01% | 1 | |
Republican | Benjamin Harrison (incumbent) | 17,519 | 48.50% | 1 | |
Democratic | Grover Cleveland | 0 | 0.00% | 1 | |
Prohibition | John Bidwell | 899 | 2.49% | 0 | |
Totals | 36,118 | 100.00% | 3 | ||
Voter turnout | — |
References
- ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – North Dakota