United States presidential election in Kansas, 1928
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Elections in Kansas | ||||||||||
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The 1928 United States presidential election in Kansas took place on November 6, 1928, as part of the 1928 United States Presidential Election which was held throughout all contemporary forty-eight states. Voters chose ten representatives, or electors to the Electoral College, who voted for president and vice president.
Kansas voted for the Republican nominee, Secretary of Commerce Herbert Hoover of California, over the Democratic nominee, Governor Alfred E. Smith of New York. Hoover’s running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith ran with Senator Joseph Taylor Robinson of Arkansas. Hoover won the by a margin of 44.96 percent.
With 72.02% of the popular vote, Kansas would prove to be Hoover's strongest state in the 1928 presidential election in terms of popular vote percentage[1].
Results
United States presidential election in Kansas, 1928[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Herbert Hoover of California | Charles Curtis of Kansas | 513,672 | 72.02% | 10 | 100.00% | ||
Democratic | Al Smith of Nebraska | Joseph Taylor Robinson of Arkansas | 193,003 | 27.06% | 0 | 0.00% | ||
Socialist | Norman Thomas of New York | James Hudson Maurer of Pennsylvania | 6,205 | 0.87% | 0 | 0.00% | ||
Communist | William Z. Foster of Massachusetts | Benjamin Gitlow of New York | 320 | 0.04% | 0 | 0.00% | ||
Total | 713,200 | 100.00% | 10 | 100.00% |
References
- ↑ "1928 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- ↑ "1928 Presidential General Election Results - Kansas". U.S. Election Atlas. Retrieved 23 December 2013.