United States presidential election in South Dakota, 1904

United States presidential election in South Dakota, 1904
November 8, 1904

 
Nominee Theodore Roosevelt Alton B. Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry G. Davis
Electoral vote 4 0
Popular vote 72,083 21,969
Percentage 71.09% 21.67%
President before election

Theodore Roosevelt
Republican

 Elected President

Theodore Roosevelt
Republican

The 1904 United States presidential election in South Dakota took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. South Dakota voters chose four electors to the Electoral College, which selected the president and vice president.

South Dakota was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. The ticket won the state by a margin of 49,42 percent.

With 71.09% of the popular vote, South Dakota would be Roosevelt's fourth strongest victory in terms of percentage in the popular vote after Vermont, North Dakota and Minnesota[1].

Results

United States presidential election in South Dakota, 1904[2]
Party Candidate Votes Percentage Electoral votes
Republican Theodore Roosevelt 72,083 71.09% 4
Democratic Alton B. Parker 21,969 21.67% 0
Social Democratic Eugene Debs 3,138 3.09% 0
Prohibition Silas C. Swallow 2,965 2.92% 0
Populist Thomas E. Watson 1,240 1.22% 0
Totals 101,395 100.00% 4
Voter turnout —

References

  1. ↑ "1904 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – South Dakota

Notes

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