United States presidential election in Kentucky, 1948
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All 11 Kentucky votes to the Electoral College | ||||||||||||||||||||||||||
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Elections in Kentucky |
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The 1948 United States presidential election in Kentucky took place on November 2, 1948, as part of the 1948 United States presidential election. Kentucky voters chose eleven[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Kentucky was won by incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 56.74% of the popular vote, against Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 41.48% of the popular vote.[3][4]
Results
Party | Candidate | Votes | % | |
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Democratic | Harry S. Truman (inc.) | 466,756 | 56.74% | |
Republican | Thomas Dewey | 341,210 | 41.48% | |
Dixiecrat | Strom Thurmond | 10,411 | 1.27% | |
Write-in | 4,281 | 0.52% | ||
Total votes | 822,658 | 100% |
References
- ↑ "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved October 30, 2017.
- ↑ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 30, 2017.
- ↑ "1948 Presidential General Election Results - Kentucky". Retrieved October 30, 2017.
- ↑ "The American Presidency Project - Election of 1948". Retrieved October 30, 2017.
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