United States presidential election in Kentucky, 1976

United States presidential election in Kentucky, 1976

November 2, 1976

Nominee Jimmy Carter Gerald Ford Party Democratic Republican Home state Georgia Michigan Running mate Walter Mondale Bob Dole Electoral vote 9 0 Popular vote 615,717 531,852 Percentage 52.8% 45.6%

County Results   Carter—80-90%   Carter—70-80%   Carter—60-70%   Carter—50-60%   Carter—<50%   Tie—<50%   Ford—50-60%   Ford—60-70%   Ford—70-80%

President before election Gerald Ford Republican Elected President Jimmy Carter Democratic

Elections in Kentucky
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Government

The 1976 United States presidential election in Kentucky took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.

Kentucky was won by Jimmy Carter (D–Georgia), with 52.75% of the popular vote. Carter defeated incumbent President Gerald Ford (R–Michigan), who finished with 45.57% of the popular vote, and did so by winning all major demographic groups in the Commonwealth.^[1] No third-party candidate amounted to 1% of the vote; American Party candidate Thomas Anderson came the closest with 0.71%.

Jimmy Carter went on to become the 39th president of the United States.^[2] As of the 2016 presidential election, this is the last election in which Warren County, Hardin County, Madison County, Christian County, Taylor County, and Lincoln County voted for the Democratic candidate, and the last in which Boone County did not support the Republican candidate.

Results

References