United States presidential election in West Virginia, 1948

United States presidential election in West Virginia, 1948
November 2, 1948[1]
All 8 West Virginia votes to the Electoral College

 
Nominee Harry S. Truman Thomas Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 8 0
Popular vote 429,188 316,251
Percentage 57.3% 42.2%
President before election

Harry S. Truman
Democratic

 Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in West Virginia took place on November 2, 1948, as part of the 1948 United States presidential election. West Virginia voters chose eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

West Virginia was won by incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 57.32% of the popular vote, against Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 42.24% of the popular vote.[3][4]

Results

United States presidential election in West Virginia, 1948
Party Candidate Votes %
Democratic Harry S. Truman (inc.) 429,188 57.32%
Republican Thomas Dewey 316,251 42.24%
Progressive Henry A. Wallace 3,311 0.44%
Total votes 748,750 100.00%

References

  1. ↑ "United States Presidential election of 1948 – Encyclopædia Britannica". Retrieved December 19, 2017.
  2. ↑ "1948 Election for the Forty-First Term (1949–53)". Retrieved December 19, 2017.
  3. ↑ "1948 Presidential General Election Results – West Virginia". Retrieved December 19, 2017.
  4. ↑ "The American Presidency Project – Election of 1948". Retrieved December 19, 2017.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.