United States presidential election in Illinois, 1948

United States presidential election in Illinois, 1948
November 2, 1948[1]
All 28 Illinois votes to the Electoral College

 
Nominee Harry S. Truman Thomas Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 28 0
Popular vote 1,994,715 1,961,103
Percentage 50.1% 49.2%
President before election

Harry S. Truman
Democratic

 Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Illinois took place on November 2, 1948, as part of the 1948 United States presidential election. Illinois voters chose twenty-eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Illinois was won by incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 50.07% of the popular vote, against Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 49.22% of the popular vote.[3][4]

Results

United States presidential election in Illinois, 1948
Party Candidate Votes %
Democratic Harry S. Truman (inc.) 1,994,715 50.07%
Republican Thomas Dewey 1,961,103 49.22%
Prohibition Claude A. Watson 11,959 0.30%
Socialist Norman Thomas 11,522 0.29%
Write-in 4,747 0.12%
Total votes 3,984,046 100%

References

  1. ↑ "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved October 26, 2017.
  2. ↑ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 26, 2017.
  3. ↑ "1948 Presidential General Election Results - Illinois". Retrieved October 26, 2017.
  4. ↑ "The American Presidency Project - Election of 1948". Retrieved October 26, 2017.
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