United States presidential election in Iowa, 1864

United States presidential election in Iowa, 1864

November 8, 1864
Turnout	19.70% of the total population 0.63 pp[1]
Nominee Abraham Lincoln George B. McClellan Party National Union Democratic Home state Illinois Pennsylvania Running mate Andrew Johnson George H. Pendleton Electoral vote 8 0 Popular vote 88,500 49,525 Percentage 64.12% 35.88%
President before election Abraham Lincoln Republican Elected President Abraham Lincoln Republican

Elections in Iowa
Federal government Presidential elections 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential caucuses Democratic 1976 1992 2000 2004 2008 2012 2016 2020 Republican 2000 2008 2012 2016 United States Senate elections 1980 1984 1986 1990 1992 1996 1998 2002 2004 2008 2010 2014 2016 United States House elections 2006 2008 2010 2012 2014 2016 2018
State government General elections 2014 2016 2018 Gubernatorial elections 1986 1990 1994 1998 2002 2006 2010 2014 2018 Iowa Senate elections 2006 2008 2010 2012 2014 2016 Iowa House elections 2006 2008 2010 2012 2014 Iowa special elections 2009

The 1864 United States presidential election in Iowa took place on November 8, 1864, as part of the 1864 United States presidential election. Iowa voters chose eight representatives, or electors, to the Electoral College, who voted for president and vice president^[2].

Iowa was won by the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 64.12% of the popular vote, against the 4th Commanding General of the United States Army George B. McClellan (D–Pennsylvania), running with Representative George H. Pendleton, with 35.88% of the vote.^[2]

Results

References