United States presidential election in Nebraska, 1900

United States presidential election in Nebraska, 1900
November 6, 1900

 
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 8 0
Popular vote 121,835 114,013
Percentage 50.46% 47.22%
President before election

William McKinley
Republican

 Elected President

William McKinley
Republican

The 1900 United States presidential election in Nebraska took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Nebraska voters chose eight electors to the Electoral College, which selected the president and vice president.

Nebraska was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.

Results

United States presidential election in Nebraska, 1900[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 121,835 50.46% 8
Democratic William Jennings Bryan 114,013 47.22% 0
Prohibition John Woolley 3,655 1.51% 0
Populist Wharton Barker 1,104 0.46% 0
Social Democratic Eugene Debs 823 0.34% 0
Totals 241,430 100.00% 8
Voter turnout —

References

  1. ↑ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Nebraska

Notes

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