United States presidential election in Vermont, 1900

United States presidential election in Vermont, 1900

November 6, 1900

Nominee William McKinley William Jennings Bryan Party Republican Democratic Home state Ohio Nebraska Running mate Theodore Roosevelt Adlai E. Stevenson Electoral vote 4 0 Popular vote 42,569 12,849 Percentage 75.73% 22.86%

President before election William McKinley Republican Elected President William McKinley Republican

Elections in Vermont
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Municipal offices Mayoral elections City of Burlington 1865 1981 1983 1985 1987 1989 1991 1993 1995 1998 2000 2003 2006 2009 2012 2015 City of Rutland 2017

The 1900 United States presidential election in Vermont took place on November 6, 1900. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont overwhelmingly voted for the Republican nominee, President William McKinley, over the Democratic nominee, former U.S. Representative and 1896 Democratic presidential nominee William Jennings Bryan. McKinley won Vermont by a landslide margin of 52.87% in this rematch of the 1896 presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.

With 75.73% of the popular vote, Vermont would be McKinley's strongest victory in terms of percentage in the popular vote^[1].

Results

Results by County

References