United States presidential election in Wisconsin, 1912
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Elections in Wisconsin | ||||||
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The 1912 United States presidential election in Wisconsin was held on November 5, 1912. Wisconsin voters chose thirteen electors to the Electoral College, who voted for president and vice president.
Democratic Party candidate Woodrow Wilson won the state with 41% of the popular vote, winning Wisconsin's thirteen electoral votes.[1] As of the 2016 presidential election, this is the last election in which Walworth County voted for the Democratic candidate.
Results
United States presidential election in Wisconsin, 1912 | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Woodrow Wilson | 164,230 | 41.06% | 13 | |
Republican | William Howard Taft | 130,596 | 32.65% | 0 | |
Progressive | Theodore Roosevelt | 62,448 | 15.61% | 0 | |
Social Democratic | Eugene V. Debs | 33,476 | 8.37% | 0 | |
Prohibition | Eugene Chafin | 8,584 | 2.15% | 0 | |
Totals | 399,334 | 100.0% | 13 | ||
References
- ↑ "1912 Presidential General Election Results - Wisconsin". Retrieved August 18, 2016.
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