United States presidential election in Vermont, 1880

United States presidential election in Vermont, 1880

November 2, 1880

 
Nominee James A. Garfield Winfield S. Hancock
Party Republican Democratic
Home state Ohio Pennsylvania
Running mate Chester A. Arthur William H. English
Electoral vote 5 0
Popular vote 45,091 18,182
Percentage 69.81% 28.15%

President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

The 1880 United States presidential election in Vermont took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 5 representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won Vermont by a margin of 41.66%.

With 69.81% of the popular vote, Vermont would be Garfield's strongest victory in terms of percentage in the popular vote[1].

Vice President-elect Chester Alan Arthur was born in Vermont, more specifically in the town of Fairfield.

Results

United States presidential election in Vermont, 1880[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Abram Garfield of Ohio Chester Alan Arthur of New York 45,091 69.81% 5 100.00%
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 18,182 28.15% 0 0.00%
Greenback James Baird Weaver of Iowa Barzillai Jefferson Chambers of Texas 1,212 1.88% 0 0.00%
N/A Others Others 109 0.17% 0 0.00%
Total 48,829 100.00% 5 100.00%

References

  1. "1880 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. "1880 Presidential General Election Results - Vermont".
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