United States presidential election in Nebraska, 1876
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Elections in Nebraska |
---|
In the 1876 United States presidential election, Nebraska voted for the Republican nominee, Ohio Governor Rutherford B. Hayes, over the Democratic nominee, New York Governor Samuel J. Tilden by a margin of 29.4%.
With 64.70% of the popular vote, Nebraska would be Hayes' second strongest victory in terms of percentage in the popular vote after Vermont[1].
Results
United States presidential election in Nebraska, 1876[2] | ||||||||
---|---|---|---|---|---|---|---|---|
Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Rutherford B. Hayes of Ohio | William A. Wheeler of New York | 31,915 | 64.70% | 3 | 100.00% | ||
Democratic | Samuel J. Tilden of New York | Thomas A. Hendricks of Indiana | 17,413 | 35.30% | 0 | 0.00% | ||
Total | 49,328 | 100.00% | 3 | 100.00% |
References
- ↑ "1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- ↑ "1876 Presidential General Election Results - Nebraska".
This article is issued from
Wikipedia.
The text is licensed under Creative Commons - Attribution - Sharealike.
Additional terms may apply for the media files.