United States presidential election in Nebraska, 1880

United States presidential election in Nebraska, 1880

November 2, 1880

Nominee James A. Garfield Winfield S. Hancock Party Republican Democratic Home state Ohio Pennsylvania Running mate Chester A. Arthur William H. English Electoral vote 3 0 Popular vote 54,979 28,523 Percentage 62.87% 32.62%

President before election Rutherford B. Hayes Republican Elected President James A. Garfield Republican

Elections in Nebraska
Federal offices Presidential elections 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential primaries Democratic Caucuses 2008 2016 Republican Primaries 2008 2012 United States Senate elections 1972 1976 1978 1982 1984 1988 1990 1994 1996 2000 2002 2006 2008 2012 2014 2018 United States House elections 2006 3rd 2008 2010 2012 2014 2016 2018
State government Gubernatorial Elections 1916 1918 1920 1922 1924 1926 1928 1930 1932 1934 1936 1938 1940 1942 1944 1946 1948 1950 1952 1954 1956 1958 1960 1962 1964 1966 1970 1974 1978 1982 1986 1990 1994 1998 2002 2006 2010 2014 State Legislature Elections 2018 General elections 2010 2014 2018
Ballot measures 2000 Initiative 416
Omaha Mayoral elections 2009 2013 2017

The 1880 United States presidential election in Nebraska took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 30.25%.

With 62.87% of the popular vote, Rhode Island would be Garfield's second strongest victory in terms of percentage in the popular vote after Vermont^[1].

Results

References