United States presidential election in Connecticut, 1788–89

United States presidential election in Connecticut, 1789

December 15, 1788 – January 10, 1789

Nominee George Washington John Adams Samuel Huntington Party Nonpartisan Federalist Federalist Home state Virginia Massachusetts Connecticut Electoral vote 7 5 2 Popular vote N/A[1] – – Percentage 100% – –

No Individual County Results

President before election George Washington Nonpartisan Elected President George Washington Nonpartisan

Elections in Connecticut
Federal government Presidential elections 1788–89 1792 1796 1800 1804 1808 1812 1816 1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential primaries Democratic 2008 2016 Republican 2008 2012 U.S. Senate elections 1940 1946 1952 1958 1964 1970 1976 1980 1982 1986 1988 1992 1994 1998 2000 2004 2006 2010 2012 2016 2018 U.S. House elections 2006 2008 2010 2012 2014 2016 2018
State government State elections 2010 2014 Gubernatorial elections 1982 1986 1990 1994 1998 2002 2006 2010 2014 2018 Attorney General elections 2010 State Senate elections 2006 2008 2010 2012 2015 State House elections 2010

The 1789 United States presidential election in Connecticut took place between December 15, 1788 – January 10, 1789 as part of the 1789 United States presidential election. The state legislature chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut, which had become the 5th state on January 9, 1788, unanimously cast its seven electoral votes for incumbent George Washington during its first presidential election.

References