United States presidential election in Connecticut, 1800

United States presidential election in Connecticut, 1800

October 31 - December 3, 1800

Nominee John Adams Charles Cotesworth Pinckney Party Federalist Federalist Home state Massachusetts South Carolina Electoral vote 9 9 Percentage 100% –

President before election John Adams Federalist Elected President Thomas Jefferson Democratic-Republican

Elections in Connecticut
Federal government Presidential elections 1788–89 1792 1796 1800 1804 1808 1812 1816 1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1864 1868 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Presidential primaries Democratic 2008 2016 Republican 2008 2012 U.S. Senate elections 1940 1946 1952 1958 1964 1970 1976 1980 1982 1986 1988 1992 1994 1998 2000 2004 2006 2010 2012 2016 2018 U.S. House elections 2006 2008 2010 2012 2014 2016 2018
State government State elections 2010 2014 Gubernatorial elections 1982 1986 1990 1994 1998 2002 2006 2010 2014 2018 Attorney General elections 2010 State Senate elections 2006 2008 2010 2012 2015 State House elections 2010

The 1800 United States presidential election in Connecticut took place between October 31 and December 3, 1800, as part of the 1800 United States presidential election. The state legislature chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, Connecticut cast nine electoral votes for incumbent Federalist President and New England native John Adams. However, Adams would lose to Democratic-Republican Party candidate Thomas Jefferson nationally.