United States presidential election in Connecticut, 1836
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Elections in Connecticut | ||||||||
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The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a margin of 1.3%.
Results
United States presidential election in Connecticut, 1836[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 19,294 | 50.65% | 8 | |
Whig | William Henry Harrison | 18,799 | 49.35% | 0 | |
Totals | 38,093 | 100.0% | 8 | ||
References
- ↑ "1836 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 4 August 2012.
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