United States presidential election in Virginia, 1836
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Elections in Virginia | ||||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|---|
|
||||||||||||
The 1836 United States presidential election in Virginia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose twenty-three representatives, or electors to the Electoral College, who voted for President and Vice President.
Virginia voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Virginia by a margin of 13.29%.
Results
United States presidential election in Virginia, 1836[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 30,556 | 56.64% | 23 | |
Whig | Hugh L. White | 23,384 | 43.35% | 0 | |
Independent | Others | 5 | 0.01% | 0 | |
Totals | 45,682 | 100.0% | 23 | ||
References
- ↑ "1836 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 12 April 2013.
This article is issued from
Wikipedia.
The text is licensed under Creative Commons - Attribution - Sharealike.
Additional terms may apply for the media files.