United States presidential election in Tennessee, 1880
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Turnout |
15.77% of the total population | |||||||||||||||||||||||||
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Elections in Tennessee |
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The 1880 United States presidential election in Tennessee took place on November 2, 1880, as part of the 1880 United States presidential election. Tennessee voters chose twelve representatives, or electors, to the Electoral College, who voted for president and vice president[2].
Tennessee was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 53.26% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 44.26% of the vote.[2]
Results
United States presidential election in Tennessee, 1880[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 129,569 | 53.26% | 12 | 100.00% | ||
Republican | James A. Garfield of Ohio | Chester A. Arthur of New York | 107,677 | 44.26% | 0 | 0.00% | ||
Greenback | James B. Weaver of Iowa | Barzillai J. Chambers of Texas | 6,017 | 2.47% | 0 | 0.00% | ||
Total | 243,263 | 100.00% | 12 | 100.00% |
References
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