1968 United States presidential election in Kentucky
The 1968 United States presidential election in Kentucky took place on November 5, 1968. All 50 states and the District of Columbia were part of the 1968 United States presidential election. Kentucky voters chose 9 electors to the Electoral College, which selected the president and vice president of the United States.
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Elections in Kentucky | ||||||
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Former Vice President Richard Nixon, the Republican nominee, won the state with 462,411 votes and 43.79% of the vote, with Vice President Hubert Humphrey, the Democratic nominee, taking 397,541 votes and 37.65% of the vote, followed by American Independent George Wallace, who took 193,098 votes and 18.29% of the vote.[2]
Results
Party | Candidate | Votes | % | |
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Republican | Richard Nixon | 462,411 | 43.79 | |
Democratic | Hubert Humphrey | 397,541 | 37.65 | |
American Independent | George Wallace | 193,098 | 18.29 | |
Socialist Workers | Fred Halstead | 2,843 | 0.27 | |
Total votes | 1,055,893 | 100% |
References
- Although he was born in California and he served as a U.S. Senator from California, in 1968 Richard Nixon's official state of residence was New York, because he moved there to practice law after his defeat in the 1962 California gubernatorial election. During his first term as president, Nixon re-established his residency in California. Consequently, most reliable reference books list Nixon's home state as New York in the 1968 election and his home state as California in the 1972 (and 1960) election.
- http://uselectionatlas.org/RESULTS/index.html
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