Greigsville, New York
Greigsville, New York | |
---|---|
Unincorporated community | |
Greigsville, New York Greigsville, New York | |
Coordinates: 42°49′50″N 77°53′49″W / 42.83056°N 77.89694°WCoordinates: 42°49′50″N 77°53′49″W / 42.83056°N 77.89694°W | |
Country | United States |
State | New York |
County | Livingston |
Area[1] | |
• Total | 0.710 sq mi (1.84 km2) |
• Land | 0.710 sq mi (1.84 km2) |
• Water | 0 sq mi (0 km2) |
Elevation | 751 ft (229 m) |
Population (2010)[1] | |
• Total | 209 |
• Density | 290/sq mi (110/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
Area code(s) | 585 |
GNIS feature ID | 951801[2] |
Greigsville is a hamlet and census-designated place in Livingston County, New York, United States. Its population was 209 as of the 2010 census.[1] The community is located at the intersection of New York State Route 36 and New York State Route 63.
Geography
According to the U.S. Census Bureau, the community has an area of 0.710 square miles (1.84 km2), all of it land.[1]
References
- 1 2 3 4 "2010 Census Gazetteer Files - Places: New York". U.S. Census Bureau. Retrieved April 3, 2017.
- ↑ "Greigsville". Geographic Names Information System. United States Geological Survey.
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