1900 United States presidential election in North Dakota
The 1900 United States presidential election in North Dakota took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Voters chose three electors to the Electoral College, which selected the president and vice president.
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Elections in North Dakota | ||||||
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North Dakota was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. McKinley won the state but a margin of 26.59%.
With 62.12% of the popular vote, North Dakota would be McKinley's second strongest victory in terms of percentage in the popular vote after Vermont.[1] McKinley had previously won the state four years earlier.
Results
1900 United States presidential election in North Dakota[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | William McKinley | 35,898 | 62.12% | 3 | |
Democratic | William Jennings Bryan | 20,531 | 35.53% | 0 | |
Prohibition | John Woolley | 731 | 1.26% | 0 | |
Social Democratic | Eugene Debs | 520 | 0.90% | 0 | |
Populist | Wharton Barker | 111 | 0.19% | 0 | |
Totals | 57,791 | 100.00% | 3 | ||
Voter turnout | — |
References
- "1900 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – North Dakota
Notes
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