1900 United States presidential election in Nebraska

The 1900 United States presidential election in Nebraska took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Voters chose eight electors to the Electoral College, which selected the president and vice president.

1900 United States presidential election in Nebraska

November 6, 1900
 
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 8 0
Popular vote 121,835 114,013
Percentage 50.46% 47.22%

President before election

William McKinley
Republican

Elected President

William McKinley
Republican

Nebraska was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.

Democratic Party candidate William Jennings Bryan lost his home state to McKinley by a margin of 3.24%. Bryan had previously defeated McKinley in the state four years earlier and would later win it again against William Howard Taft in 1908.

Results

1900 United States presidential election in Nebraska[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 121,835 50.46% 8
Democratic William Jennings Bryan 114,013 47.22% 0
Prohibition John Woolley 3,655 1.51% 0
Populist Wharton Barker 1,104 0.46% 0
Social Democratic Eugene Debs 823 0.34% 0
Totals 241,430 100.00% 8
Voter turnout

References

  1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Nebraska

Notes

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