1892 United States presidential election in Iowa

The 1892 United States presidential election in Iowa took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Iowa voters chose thirteen electors to the Electoral College, which selected the president and vice president.

Main article: 1892 United States presidential election
1892 United States presidential election in Iowa
November 8, 1892
 
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Whitelaw Reid Adlai Stevenson I
Electoral vote 13 0
Popular vote 219,795 196,367
Percentage 49.60% 44.31%
President before election

Benjamin Harrison
Republican

 Elected President

Grover Cleveland
Democratic

Elections in Iowa

Iowa was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York.

Results
1892 United States presidential election in Iowa[1]
Party Candidate Votes Percentage Electoral votes
Republican Benjamin Harrison (incumbent) 219,795 49.60% 13
Democratic Grover Cleveland 196,367 44.31% 0
People's James Weaver 20,595 4.65% 0
Prohibition John Bidwell 6,402 1.44% 0
Totals 443,159 100.00% 13
Voter turnout —

References
  1. Dave Leip's U.S. Election Atlas; https://uselectionatlas.org/RESULTS/state.php?fips=19&year=1892&f=0&off=0&elect=0 Presidential General Election Results – Iowa]

Notes
    This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.