1848 United States presidential election in Iowa
The 1848 United States presidential election in Iowa took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
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| Elections in Iowa | ||||||||||
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Iowa voted for the Democratic candidate Lewis Cass in the state's first presidential election, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Iowa by a margin of 5.87%.
Results
| 1848 United States presidential election in Iowa[1][2] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Lewis Cass of Michigan | William O. Butler of Kentucky | 11,238 | 50.46% | 4 | 100.00% | ||
| Whig | Zachary Taylor of Louisiana | Millard Fillmore of New York | 9,930 | 44.59% | 0 | 0.00% | ||
| Free Soil | Martin Van Buren of New York | Charles F. Adams, Sr. of Massachusetts | 1,103 | 4.95% | 0 | 0.00% | ||
| Total | '22,271 | 100.00% | 4 | 100.00% | ||||
References
- "1848 Presidential General Election Results - Iowa". U.S. Election Atlas. Retrieved 27 December 2013.
- "1848 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 27 December 2013.
State and district results of the 1848 United States presidential election | ||
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