1868 United States presidential election in Georgia

The 1868 United States presidential election in Georgia took place on November 3, 1868, as part of the wider United States Presidential election. Voters chose 9 representatives, or electors, to the Electoral College, who voted for president and vice president.

United States presidential election in Georgia, 1868

November 3, 1868 (1868-11-03)
 
Nominee Horatio Seymour Ulysses S. Grant
Party Democratic Republican
Home state New York Ohio
Running mate Francis P. Blair, Jr. Schuyler Colfax
Electoral vote 9 0
Popular vote 102,707 57,109
Percentage 64.27% 35.73%

President before election

Andrew Johnson
National Union

Elected President

Ulysses S. Grant
Republican

Background

The first readmission of Georgia to the Union occurred in 1868.

Vote

The Seymour/Blair ticket carried the state of Georgia on election day.

With 64.27% of the popular vote, Georgia would be Seymour's fourth strongest victory in terms of percentage in the popular vote after Kentucky, Louisiana and Maryland.[1]

Results

United States presidential election in Georgia, 1868 [2]
Party Candidate Votes Percentage Electoral votes
Democratic Horatio Seymour 102,707 64.27% 9
Republican Ulysses S. Grant 57,109 35.73% 0

References

  1. "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. Dave Leip’s U.S. Election Atlas; 1868 Presidential General Election Results – Georgia

Notes

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